![]() ![]() Once we get the doubt that how JVM is handling all this internally? or how JVM is calculating which method it should call.Īlso, we know that overloaded methods are not called polymorphic and get resolved at compile time and this is why sometimes method overloading is also known as compile time polymorphism or early/static binding.īut overridden methods get resolved at runtime time because the compiler does not know that, the object which we are assigning to our reference have overridden the method or not. Well, it is pretty simple until we keep it at the conceptual level only. But at execution time method will be called from the object which the reference is holding. Logically we can say, during compilation phase calling method is considered from the reference type. We can answer this answer in two ways, Logical way and Physical way, let's take a look at the logical way. ![]() 42: invokevirtual #9 // Method org/programming/mitra/exercises/OverridingInternalExample$Human.speak:(Ljava/lang/String )V 36: invokevirtual #7 // Method org/programming/mitra/exercises/OverridingInternalExample$Human.speak:()V 23: invokevirtual #4 // Method org/programming/mitra/exercises/OverridingInternalExample$Mammal.speak:()V 10: invokevirtual #4 // Method org/programming/mitra/exercises/OverridingInternalExample$Mammal.speak:()V Code below contains the output and and bytecode of the method callsĪnyMammal.speak() // Output - ohlllalalalalalaoaoaoa Let’s take the example of a parent class MammalĬlasses from our previous blog to understand it more clearly. In this article, we will see How Does JVM Handle Method Overloading And Overriding Internally, how JVM identifies which method should get called. ![]() ![]() In my previous article Everything About Method Overloading Vs Method Overriding, I have discussed method overloading and overriding, their rules and differences. ![]()
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